Titanium is a transition metal. Titanium is extracted from titanium dioxide in a two-stage industrial process. Stage 1 TiO2 + 2 C + 2 Cl2 ⟶ TiCl4 + 2 CO Stage 2 TiCl4 + 4 Na ⟶ Ti + 4 NaCl In Stage 2, 40 kg of titanium chloride was added to 20 kg of sodium. The equation for the reaction is: TiCl4 + 4 Na ⟶ Ti + 4 NaCl Relative atomic masses (Ar): Na = 23 Cl = 35.5 Ti = 48 Explain why titanium chloride is the limiting reactant. You must show your working. – 6153

Q1.

Titanium is a transition metal.

Titanium is extracted from titanium dioxide in a two-stage industrial process.

Stage 1 TiO2 + 2 C + 2 Cl2 ⟶ TiCl4 + 2 CO

Stage 2 TiCl4 + 4 Na ⟶ Ti + 4 NaCl

In Stage 2, 40 kg of titanium chloride was added to 20 kg of sodium.

The equation for the reaction is:

TiCl4 + 4 Na ⟶ Ti + 4 NaCl

Relative atomic masses (Ar): Na = 23 Cl = 35.5 Ti = 48

Explain why titanium chloride is the limiting reactant.

You must show your working.

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One thought on “Titanium is a transition metal. Titanium is extracted from titanium dioxide in a two-stage industrial process. Stage 1 TiO2 + 2 C + 2 Cl2 ⟶ TiCl4 + 2 CO Stage 2 TiCl4 + 4 Na ⟶ Ti + 4 NaCl In Stage 2, 40 kg of titanium chloride was added to 20 kg of sodium. The equation for the reaction is: TiCl4 + 4 Na ⟶ Ti + 4 NaCl Relative atomic masses (Ar): Na = 23 Cl = 35.5 Ti = 48 Explain why titanium chloride is the limiting reactant. You must show your working. – 6153

  1. First, I worked out the Mr of TiCl₄, which is 190.

    Then I worked out the moles of sodium:
    20,000/23=870 mol

    Next, I calculated the moles of TiCl₄:
    40,000/ 190 = 211 mol

    The balanced equation shows we need 4 moles of sodium for every 1 mole of TiCl₄,
    so for 211 mol of TiCl₄, we need:

    211 × 4 = 844 mol of Na

    But we have 870 mol of Na, which is more than 844,
    so sodium is in excess.

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