A student investigated the thermal conductivity of different metals. This is the method used: 1. Measure the mass of an ice cube. 2. Put the ice cube on a metal block which is at room temperature. 3. Measure the mass of the ice cube after one minute. 4. Repeat with other blocks of the same mass made from different metals. – 6047

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Q1.

A student investigated the thermal conductivity of different metals. 

This is the method used: 

1. Measure the mass of an ice cube. 

2. Put the ice cube on a metal block which is at room temperature.

 3. Measure the mass of the ice cube after one minute. 

4. Repeat with other blocks of the same mass made from different metals.

The following table shows the student’s results.

An ice cube has a temperature of −15.0 °C 

The total thermal energy needed to raise the temperature of this ice cube to 0.0 °C and completely melt the ice cube is 5848 J 

specific heat capacity of ice = 2100 J/kg °C 

specific latent heat of fusion of ice = 334 000 J/kg 

Calculate the mass of the ice cube.

___________________________________________________________________ ___________________________________________________________________ ___________________________________________________________________ ___________________________________________________________________ ___________________________________________________________________ ___________________________________________________________________ ___________________________________________________________________ ___________________________________________________________________ 

Mass of ice cube = _____________________________ kg (5)

  1. Fatima Siddiqui Avatar
    Fatima Siddiqui

    𝐸=m×2100×15
    E=𝑚×31500
    Total energy = energy to melt + energy to heat
    5848=𝑚×334000+𝑚×31500
    5848=m×(334000+31500)
    5848=m×365,500
    m= 5848/365500
    m=0.016kg

    ​

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One thought on “A student investigated the thermal conductivity of different metals. This is the method used: 1. Measure the mass of an ice cube. 2. Put the ice cube on a metal block which is at room temperature. 3. Measure the mass of the ice cube after one minute. 4. Repeat with other blocks of the same mass made from different metals. – 6047”

  1. 𝐸=m×2100×15
    E=𝑚×31500
    Total energy = energy to melt + energy to heat
    5848=𝑚×334000+𝑚×31500
    5848=m×(334000+31500)
    5848=m×365,500
    m= 5848/365500
    m=0.016kg

    ​

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