Another student carried out the titration accurately. 12.15 cm3 of dilute sulfuric acid with a concentration of 0.140 mol dm–3 reacted completely with 25.00 cm3 of potassium hydroxide solution. H2SO4 + 2KOH → K2SO4 + 2H2O . Calculate the concentration of this potassium hydroxide solution – 9040

One thought on “Another student carried out the titration accurately. 12.15 cm3 of dilute sulfuric acid with a concentration of 0.140 mol dm–3 reacted completely with 25.00 cm3 of potassium hydroxide solution. H2SO4 + 2KOH → K2SO4 + 2H2O . Calculate the concentration of this potassium hydroxide solution – 9040”

1. moles of H2SO4=0.140×12.15/1000=0.001701 mol
   moles of KOH=2×0.001701=0.003402 mol
   concentration of KOH=0.003402×1000//25.00=0.136 mol dm−3

   Reply