Figure 1 shows the displayed formula equation for the reaction of hydrogen sulfide with oxygen. Figure 1 2 H – S – H + 3 O=O ….> 2 H-O-H + 2 O=S=O. – 6013

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Q1.

Figure 1 shows the displayed formula equation for the reaction of

hydrogen sulfide with oxygen.

Figure 1

2 H – S – H + 3 O=O ….> 2 H-O-H + 2 O=S=O

The table below shows some of the bond energies

In the reaction the energy released forming new bonds is 1034 kJ/mol

greater than the energy needed to break existing bonds.

Calculate the bond energy X for the bond.

Use Figure 1 and the table above.

___________________________________________________________

X = _______________kJ/mol

(5)

  1. Isha Reddy Avatar
    Isha Reddy

    Step 1: Calculate bonds broken
    C–H bonds:
    4
    ×
    364
    =
    1456
    4×364=1456
    C–C bonds:
    3
    ×
    498
    =
    1494
    3×498=1494
    Total bonds broken =
    1456
    +
    1494
    =
    2950

    kJ/mol
    1456+1494=2950kJ/mol

    Step 2: Add energy change (given)
    Bonds formed =
    2950
    +
    1034
    =
    3984

    kJ/mol
    2950+1034=3984kJ/mol

    Step 3: Set up equation for unknown bond X
    Bonds formed =
    4
    𝑋
    +
    4
    ×
    464
    4X+4×464
    So,
    4
    𝑋
    +
    1856
    =
    3984
    4X+1856=3984

    Step 4: Rearrange to solve for X
    4
    𝑋
    =
    3984

    1856
    =
    2128
    4X=3984−1856=2128

    Step 5: Divide to find X
    𝑋
    =
    2128
    4
    =
    532

    kJ/mol
    X=
    4
    2128

    =532kJ/mol

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One thought on “Figure 1 shows the displayed formula equation for the reaction of hydrogen sulfide with oxygen. Figure 1 2 H – S – H + 3 O=O ….> 2 H-O-H + 2 O=S=O. – 6013

  1. Step 1: Calculate bonds broken
    C–H bonds:
    4
    ×
    364
    =
    1456
    4×364=1456
    C–C bonds:
    3
    ×
    498
    =
    1494
    3×498=1494
    Total bonds broken =
    1456
    +
    1494
    =
    2950

    kJ/mol
    1456+1494=2950kJ/mol

    Step 2: Add energy change (given)
    Bonds formed =
    2950
    +
    1034
    =
    3984

    kJ/mol
    2950+1034=3984kJ/mol

    Step 3: Set up equation for unknown bond X
    Bonds formed =
    4
    𝑋
    +
    4
    ×
    464
    4X+4×464
    So,
    4
    𝑋
    +
    1856
    =
    3984
    4X+1856=3984

    Step 4: Rearrange to solve for X
    4
    𝑋
    =
    3984

    1856
    =
    2128
    4X=3984−1856=2128

    Step 5: Divide to find X
    𝑋
    =
    2128
    4
    =
    532

    kJ/mol
    X=
    4
    2128

    =532kJ/mol

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