Solid lead reacts with nitric acid, HNO3. Lead nitrate, Pb(NO3)2, nitrogen oxide, NO, and water are made. How many moles of lead nitrate would be produced if 20.7 g of lead reacts with nitric acid? Give your answer to 2 significant figures. – 7558

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1. • Mr(Pb(NO3)2)=331.2
   •
   • 207 g Pb → 331.2 g Pb(NO₃)₂, so 20.7 g Pb → 33.12 g Pb(NO₃)₂.
   • Moles of Pb(NO₃)₂ =mass / Mr=33.1 / 331.2=0.0999≈0.10 mol .
   OR (mole ratio method):
   • Ratio Pb : Pb(NO₃)₂ is 1:1
   • n(Pb)=20.7 / 207 = 0.100 mol⇒n(Pb(NO3)2)=0.10 mol

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