The diagram below shows part of a mains electricity lighting circuit in a house. A fault in the switch caused a householder to receive a mild electric shock before a safety device switched the circuit off. The mean power transfer to the person was 5.75 W. The potential difference across the person was 230 V. Calculate the resistance of the person. – 6002

Home > GCSE & A Levels Revision Questions

The current image has no alternative text. The file name is: yrq8_t3aw_210702.jpg

Q1.         

The diagram below shows part of a mains electricity lighting circuit in a house.

A fault in the switch caused a householder to receive a mild electric shock before a safety

device switched the circuit off.

The mean power transfer to the person was 5.75 W.

The potential difference across the person was 230 V.

Calculate the resistance of the person.

___________________________________________________________________

___________________________________________________________________

___________________________________________________________________

Resistance = _______________Ω

(5)

  1. Dev Patel Avatar
    Dev Patel

    P = I × V

    5.75 = I × 230
    I = 5.75 ÷ 230 = 0.025 A

    V = I R
    R = V ÷ I = 230 ÷ 0.025
    R = 9200 Ω

Leave a Reply

Your email address will not be published. Required fields are marked *

Was this article helpful?
YesNo

One thought on “The diagram below shows part of a mains electricity lighting circuit in a house. A fault in the switch caused a householder to receive a mild electric shock before a safety device switched the circuit off. The mean power transfer to the person was 5.75 W. The potential difference across the person was 230 V. Calculate the resistance of the person. – 6002

  1. P = I × V

    5.75 = I × 230
    I = 5.75 ÷ 230 = 0.025 A

    V = I R
    R = V ÷ I = 230 ÷ 0.025
    R = 9200 Ω

Leave a Reply

Your email address will not be published. Required fields are marked *