The table shows the student’s results. The equation for the reaction is: C6H8O7 + 3 NaOH ⟶ C6H5O7Na3 + 3 H2O The concentration of the sodium hydroxide was 0.102 mol / dm3 Concordant results are those within 0.10 cm3 of each other. Calculate the concentration of the citric acid in mol / dm3 Use only the concordant results from the table in your calculation. You must show your working. – 6122

Q1.

The table shows the student’s results.

The equation for the reaction is: 

C6H8O7 + 3 NaOH ⟶ C6H5O7Na3 + 3 H2O 

The concentration of the sodium hydroxide was 0.102 mol / dm3 

Concordant results are those within 0.10 cm3 of each other. 

Calculate the concentration of the citric acid in mol / dm3 

Use only the concordant results from the table in your calculation. 

You must show your working.

___________________________________________________________ ___________________________________________________________ ___________________________________________________________ ___________________________________________________________ ___________________________________________________________ ___________________________________________________________ ___________________________________________________________ 

Concentration = ____________________ mol / dm3 (5)

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One thought on “The table shows the student’s results. The equation for the reaction is: C6H8O7 + 3 NaOH ⟶ C6H5O7Na3 + 3 H2O The concentration of the sodium hydroxide was 0.102 mol / dm3 Concordant results are those within 0.10 cm3 of each other. Calculate the concentration of the citric acid in mol / dm3 Use only the concordant results from the table in your calculation. You must show your working. – 6122

  1. 12.10+12.15+12.15/3=12.13 cm3
    moles=concentration×volume=0.10×12.13/1000=0.00255 mol
    1/3×moles of NaOH=1/3×0.00255=0.00085 mol
    concentration=moles/volume=0.00085/0.01213=0.0701 mol/dm3

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